b^2+4b+4/2b^2+3b-2

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Solution for b^2+4b+4/2b^2+3b-2 equation: 


b in (-oo:+oo)

b^2+(4/2)*b^2+4*b+3*b-2 = 0

3*b^2+7*b-2 = 0

DELTA = 7^2-(-2*3*4)

DELTA = 73

DELTA > 0

b = (73^(1/2)-7)/(2*3) or b = (-73^(1/2)-7)/(2*3)

b = (73^(1/2)-7)/6 or b = (-(73^(1/2)+7))/6

b in { (-(73^(1/2)+7))/6, (73^(1/2)-7)/6 }

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